How to obtain a Zinc Chromate of high hiding strength

by Adolfo Rios Pita G.

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1.- Na2Cr2O7 + H2SO4 + H2O = 2CrO4H2 + Na2SO4

2.-CrO4H2 + ZnO = ZnCrO4 + H2O

3.- 4ZnCrO4 + 2NaOH + 2H2O = 4ZnO.Na2O.4CrO3.3H2O

 

Process to obtain a batch of 100 kilograms of HHS Zinc Chromate

 

Solution "a": Dissolve 62.31 kgs. of sodium bichromate in the double of its weight in water = 124.62 liters.

Add to this solution 15.73 kgs. of concentrated sulfuric acid ( this is 8.49 liters -1,25 times the stoichiometric amount-).

 

Solution "b": Prepare a suspension of 38.7 kgs. of zinc oxide in about 250 liters of water.

 

Procedure:

Stirring , pour the solution "a" over the suspension "b". This is done in 20 minutes.

Then, 48.6 liters of sodium hydroxide ( concentration= 48% -4,3 times the stoichiometric amount-) are added until pH is > 10.3

The precipitate is then filtered and slightly washed.

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